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SSC JE CE Previous Year Paper 9 (Held on 30 Oct 2020 Morning)

Option 2 : 90 kN-m

ST 1: Building Material and Concrete Technology

18104

20 Questions
20 Marks
12 Mins

Given:

**Maximum bending moment at C:**

Maximum bending moment at C will occur when average loading just to the left of C is equal to average loading just to right of C.

\(\frac{x}{{5 - x}} = \frac{4}{6}\)

So, x = 2 m

Maximum bending moment = Area of ILD below loading (rectangle + triangle) × w

= [(1.2 × 5) + 0.5 × (5 × 1.2)] × 10

= 90 KN-m